A) NAIB
B) 2NAIB
C) \[2\pi NAIB\]
D) \[4\pi NAIB\]
Correct Answer: B
Solution :
\[W=MB\left( \cos {{\theta }_{1}}-\cos {{\theta }_{2}} \right)\] \[=(NiA)\ B(\cos 0{}^\circ -\cos 180{}^\circ )=2NAIB\]You need to login to perform this action.
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