A) \[\frac{{{\mu }_{0}}{{i}^{2}}}{{{b}^{2}}}\]
B) \[\frac{{{\mu }_{0}}{{i}^{2}}}{2\pi b}\]
C) \[\frac{{{\mu }_{0}}i}{2\pi b}\]
D) \[\frac{{{\mu }_{0}}i}{2\pi {{b}^{2}}}\]
Correct Answer: B
Solution :
Force per unit length \[=\frac{{{\mu }_{0}}}{4\pi }.\frac{2{{i}_{1}}{{i}_{2}}}{r}=\frac{{{\mu }_{0}}}{2\pi }.\frac{{{i}^{2}}}{b}\]
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