A) \[8\times {{10}^{-5}}N\]
B) \[4\times {{10}^{-7}}N\]
C) \[4\times {{10}^{-5}}N\]
D) \[4\pi \times {{10}^{-7}}N\]
Correct Answer: A
Solution :
\[F=\frac{{{\mu }_{0}}}{4\pi }.\frac{2{{i}_{1}}{{i}_{2}}}{a}\times l\]\[\Rightarrow F={{10}^{-7}}\times \frac{2\times 10\times 2}{(10\times {{10}^{-2}})}\times 2=8\times {{10}^{-5}}N\]
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