A) 2.0 A
B) \[2.0\times {{10}^{-7}}A\]
C) 1.0 A
D) \[1.0\times {{10}^{-7}}A\]
Correct Answer: C
Solution :
\[\frac{F}{l}=\frac{{{\mu }_{0}}}{4\pi }\times \frac{2{{i}_{1}}{{i}_{2}}}{a}=\frac{{{\mu }_{0}}}{4\pi }\frac{2{{i}^{2}}}{a}\ \ (\because \ {{i}_{1}}={{i}_{2}}=i)\] \[\Rightarrow 2\times {{10}^{-7}}={{10}^{-7}}\times \frac{2{{i}^{2}}}{1}\Rightarrow i=1A\]
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