A) 10-3 N
B) 2.5 ´ 10-3 N
C) Zero
D) 1.5 ´ 10-3 N
Correct Answer: C
Solution :
Force on wire C due to wire D \[{{F}_{D}}={{10}^{-7}}\times \frac{2\times 30\times 10}{2\times {{10}^{-2}}}\times 25\times {{10}^{-2}}=5\times {{10}^{-4}}N\] (towards right) Force on wire C due to wire G \[{{F}_{G}}={{10}^{-7}}\times \frac{2\times 20\times 10}{2\times {{10}^{-2}}}\times 25\times {{10}^{-2}}=5\times {{10}^{-4}}N\] (towards left) Þ Net force on wire C is \[{{F}_{net}}={{F}_{D}}-{{F}_{G}}=0\]You need to login to perform this action.
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