A) \[{{F}_{1}}=2{{F}_{2}}\]
B) \[{{F}_{2}}=2{{F}_{1}}\]
C) \[{{F}_{1}}={{F}_{2}}\]
D) \[{{F}_{1}}=-{{F}_{2}}\]
Correct Answer: D
Solution :
\[F=\frac{{{\mu }_{0}}}{4\pi }\frac{2{{i}_{1}}{{i}_{2}}}{a}\] \[{{F}_{1}}=\frac{{{\mu }_{0}}}{4\pi }=\frac{2{{i}^{2}}}{x}\] (Attraction) \[{{F}_{2}}=\frac{{{\mu }_{0}}}{4\pi }=\frac{2i\times 2i}{2x}=\frac{{{\mu }_{0}}}{4\pi }\frac{2{{i}^{2}}}{x}\] (Repulsion) Thus \[{{F}_{1}}=-{{F}_{2}}\]
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