A) Zero
B) IBl
C) \[\frac{\sqrt{3}}{2}I{{l}^{2}}{{B}^{2}}\]
D) \[\frac{\sqrt{3}}{4}IB{{l}^{2}}\]
Correct Answer: D
Solution :
Since q = 90° Hence \[\tau =NIAB=1\times I\times \left( \frac{\sqrt{3}}{4}{{l}^{2}} \right)\,B\] \[=\frac{\sqrt{3}}{4}{{l}^{2}}B\]You need to login to perform this action.
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