A) \[{{y}^{2}}\frac{dy}{dx}={{x}^{2}}\]
B) \[{{x}^{2}}\frac{dy}{dx}={{y}^{2}}\]
C) \[y\frac{dy}{dx}=x\]
D) \[x\frac{dy}{dx}=y\]
Correct Answer: B
Solution :
\[y=\frac{x}{x+1}\Rightarrow \frac{1}{y}=1+\frac{1}{x}\] \[-\frac{1}{{{y}^{2}}}\frac{dy}{dx}=0-\frac{1}{{{x}^{2}}}\] Þ \[{{x}^{2}}\frac{dy}{dx}={{y}^{2}}\].You need to login to perform this action.
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