A) \[\frac{12}{11}\]
B) \[\frac{11}{12}\]
C) \[0\]
D) \[\frac{13}{12}\]
Correct Answer: B
Solution :
\[\left( \frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}......+\frac{1}{11}-\frac{1}{12} \right)\] \[=1-\frac{1}{12}=\frac{11}{12}\]You need to login to perform this action.
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