7th Class Mathematics Decimals and Fractions Question Bank Fractions and Decimals

  • question_answer
    If \[63.9805=6A+\frac{3}{B}+9C+\frac{8}{D}+5E,\] then what is the value of \[4A+7B+6C+D+3E\]?

    A)  \[47.603\]                   

    B)  \[4.7603\]       

    C)         \[147.6003\]    

    D)         \[47.6003\]       

    Correct Answer: C

    Solution :

    \[63.9805=6\times 10+3\times 1+9\times \frac{1}{10}\] \[+8\times \frac{1}{100}+5\times \frac{1}{10000}\] \[\therefore \]  \[A=10,\,B=1,\,C=\frac{1}{10},\,D=100,\,E=\frac{1}{10000}\] \[\therefore \]  \[4A+7B+6C+D+3E\] \[=4\times 10+7\times 1+6\times \frac{1}{10}+100+3\times \frac{1}{10000}\] \[=4+7+0.6+100+0.0003=147.6003\]


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