A) \[\frac{1}{6}\]
B) \[\frac{1}{3}\]
C) 1
D) \[\frac{5}{6}\]
Correct Answer: C
Solution :
Given: \[=\frac{7}{6}\]and \[+\frac{1}{2}=\frac{2}{3}\] \[\therefore \] \[=\frac{2}{3}-\frac{1}{2}=\frac{2\times 2}{3\times 2}-\frac{1\times 3}{2\times 3}=\frac{1}{6}\] Since, \[=\frac{7}{6},\]we get \[\frac{1}{6}+\]You need to login to perform this action.
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