| \[\frac{\mathbf{1}}{\mathbf{3}}\mathbf{+}\frac{\mathbf{2}}{\mathbf{9}}\mathbf{=}\frac{\mathbf{N+1}}{\mathbf{N+5}}\] |
A) 5
B) \[\frac{5}{9}\]
C) 4
D) 9
Correct Answer: C
Solution :
\[\frac{1}{3}+\frac{2}{9}=\frac{1\times 3}{3\times 3}+\frac{2}{9}=\frac{4+1}{4+5}\] Comparing the sum obtained with \[\frac{\text{N + 1}}{\text{N + 5}}\] we get N = 4.
You need to login to perform this action.
You will be redirected in
3 sec
