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JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Free energy and work function

  • question_answer
    The \[\Delta H\] and \[\Delta S\] for a reaction at one atmospheric pressure are +30.558 kJ and \[0.066\,kJ{{k}^{-1}}\] respectively. The temperature at which the free energy change will be zero and below of this temperature the nature of reaction would be      [Kerala CET 2005]

    A)                 483 K, spontaneous

    B)                 443 K, non-spontaneous

    C)                 443 K, spontaneous

    D)                 463 K, non-spontaneous

    E)                 463 K, spontaneous

    Correct Answer: D

    Solution :

               \[\Delta G=\Delta H-T\Delta S\]                    \[0=+30.558-T\times 0.066\]                    or  \[T=\frac{30.558}{0.066}=463K\]                                 If \[{{(dG)}_{T,P}}=0\] sign \['='\] mean. If is reversible process


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