A) \[f(a)+f(a-x)\]
B) \[f(-x)\]
C) \[-f(x)\]
D) \[f(x)\]
Correct Answer: C
Solution :
\[f(a-(x-a))=f(a)f(x-a)-f(0)f(x)\] .....(i) Put \[x=0,y=0\]; \[f(0)={{(f(0))}^{2}}-{{[f(a)]}^{2}}\Rightarrow f(a)=0\] \[[\because f(0)=1].\] From (i), \[f(2a-x)=-f(x)\].You need to login to perform this action.
You will be redirected in
3 sec