A) x
B) ?x
C) \[\frac{x}{2}\]
D) \[-\frac{1}{x}\]
Correct Answer: A
Solution :
\[f\,[f(x)]=\frac{f(x)-3}{f(x)+1}\] \[=\frac{\left( \frac{x-3}{x+1} \right)-3}{\left( \frac{x-3}{x+1} \right)+1}=\frac{x-3-3x-3}{x-3+x+1}=\frac{3+x}{1-x}\] Now \[f\,[f(f(x))]=f\,\left( \frac{3+x}{1-x} \right)\] \[f(x)=(2,\,4]-\{3\}\].You need to login to perform this action.
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