A) \[2x\]
B) \[2|x|\]
C) \[-2x\]
D) \[-2|x|\]
Correct Answer: B
Solution :
\[f(2x)=2(2x)+|2x|\,=4x+2|x|\], \[y={{x}^{2}}+1\], \[f(x)=2x+|x|\] Þ \[f(2x)+f(-x)-f(x)\] \[=4x+2|x|+|x|-2x-2x-|x|\]\[=2\,\,|x|\].You need to login to perform this action.
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