A) One-one onto
B) One-one into
C) Many-one onto
D) Many-one into
Correct Answer: D
Solution :
\[\because f(0)=f(-1)=0\] hence \[f(x)\] is many one. But there is no pre-image of \[-1\]. Hence \[f(x)\] is into function. So function is many-one into.You need to login to perform this action.
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