A) \[[-4,\ \infty )\]
B) [?4, 4]
C) [0, 4]
D) [0, 1]
Correct Answer: D
Solution :
\[f(x)=\sqrt{x-{{x}^{2}}}+\sqrt{4+x}+\sqrt{4-x}\] Clearly \[f(x)\] is defined, if \[4+x\ge 0\] Þ \[x\ge -4\] \[4-x\ge 0\] Þ \[x\le 4\] \[x(1-x)\ge 0\] Þ \[x\ge 0\] and \[x\le 1\] \ Domain of \[f=(-\infty ,\,4]\cap [-4,\,\infty )\cap [0,\,1]\]\[=[0,\,1]\].You need to login to perform this action.
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