A) (2, 3)
B) [2, 3]
C) [1, 2]
D) [1, 3]
Correct Answer: B
Solution :
\[\log \,\left\{ \frac{5x-{{x}^{2}}}{6} \right\}\,\ge 0\,\,\Rightarrow \,\frac{5x-{{x}^{2}}}{6}\ge 1\] or \[{{x}^{2}}-5x+6\le 0\] or \[(x-2)\,(x-3)\le 0\]. Hence \[2\le x\le 3.\]
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