A) (1, 2)
B) \[(-1,\ 0)\cup (1,\ 2)\]
C) \[(1,\ 2)\cup (2,\ \infty )\]
D) \[(-1,\ 0)\cup (1,\ 2)\cup (2,\ \infty )\]
Correct Answer: D
Solution :
\[f(x)=\frac{3}{4-{{x}^{2}}}+{{\log }_{10}}({{x}^{3}}-x)\]. So, \[4-{{x}^{2}}\ne 0\]Þ \[x\ne \pm \sqrt{4}\] and \[{{x}^{3}}-x>0\Rightarrow x({{x}^{2}}-1)>0\] Þ \[x>0,\,x>1\] \\[D=(-1,\,0)\cup (1,\,\infty )-\{\sqrt{4}\}\]i.e.,\[D=(-1,\,0)\cup (1,\,2)\cup (2,\,\infty )\].You need to login to perform this action.
You will be redirected in
3 sec