A) \[\frac{1}{4}\]
B) \[\frac{1}{3}\]
C) \[\frac{1}{2}\]
D) None of these
Correct Answer: A
Solution :
\[\frac{1}{2}\int_{0}^{\pi /8}{{{\sec }^{2}}2xdx=\frac{1}{4}[\tan 2x]_{0}^{\pi /8}}=\frac{1}{4}[1]=\frac{1}{4}\].
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