JEE Main & Advanced Mathematics Definite Integration Question Bank Fundamental definite integration, Definite integration by substitution

  • question_answer
    \[\int_{0}^{\pi /3}{\cos 3x\,dx=}\]                                           [SCRA 1980]

    A)                 \[\pi \] 

    B)                 0

    C)                 \[\frac{\pi }{2}\]              

    D)                 \[\frac{\pi }{4}\]

    Correct Answer: B

    Solution :

                    Required value is \[\left[ \frac{\sin 3x}{3} \right]_{0}^{\pi /3}=0\].


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