JEE Main & Advanced Mathematics Definite Integration Question Bank Fundamental definite integration, Definite integration by substitution

  • question_answer
    The value of \[\int_{\,-\,1}^{\,3}{\,{{\tan }^{-1}}\left( \frac{x}{{{x}^{2}}+1} \right)+{{\tan }^{-1}}\left( \frac{{{x}^{2}}+1}{x} \right)\,dx}\] is                 [Karnataka CET 2000]

    A)                 \[2\pi \]               

    B)                 \[\pi \]

    C)                 \[\frac{21}{5}\pi \]          

    D)                 \[\frac{\pi }{4}\]

    Correct Answer: A

    Solution :

               \[I=\int_{-1}^{3}{\left[ {{\tan }^{-1}}\left( \frac{x}{{{x}^{2}}+1} \right)+{{\cot }^{-1}}\left( \frac{x}{{{x}^{2}}+1} \right) \right]\,dx}\]                                 \[=\int_{-1}^{3}{\left( \frac{\pi }{2} \right)\,dx=\left[ \frac{\pi \,x}{2} \right]_{-1}^{3}=2\pi }\],  \[\left( \because {{\tan }^{-1}}(x)+{{\cot }^{-1}}(x)=\frac{\pi }{2} \right)\].


You need to login to perform this action.
You will be redirected in 3 sec spinner