A) \[\frac{\pi }{2}\]
B) \[\int_{0}^{\pi /2}{\frac{\sin x}{x}\,dx}\]
C) Nothing can be said
D) None of these
Correct Answer: A
Solution :
Since \[\sin x<x\] for \[0<x\le \pi /2\] So, \[\int_{0}^{^{\pi /2}}{\frac{\sin x}{x}dx<\int_{0}^{\pi /2}{1dx=\frac{\pi }{2}}}\].You need to login to perform this action.
You will be redirected in
3 sec