A) \[{{I}_{1}}={{I}_{2}}\]
B) \[{{I}_{1}}>{{I}_{2}}\]
C) \[{{I}_{1}}<{{I}_{2}}\]
D) None of these
Correct Answer: A
Solution :
Put \[\log x=u\]in \[{{I}_{1}},\]so that \[dx=x\,du={{e}^{u}}du\] Also as \[x=e\]to \[{{e}^{2}},u=1\]to 2 Thus, \[{{I}_{1}}=\int_{1}^{2}{\frac{{{e}^{u}}}{u}du=\int_{1}^{2}{\frac{{{e}^{x}}}{x}dx}}\]. Hence, \[{{I}_{1}}={{I}_{2}}\].You need to login to perform this action.
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