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JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Fundamental Integration

  • question_answer
    \[\int_{{}}^{{}}{\left( 1+x+\frac{{{x}^{2}}}{2\ !}+\frac{{{x}^{3}}}{3\ !}+.......... \right)\ dx=}\]

    A)            \[-{{e}^{x}}+c\]

    B)            \[{{e}^{x}}+c\]

    C)            \[{{e}^{-x}}+c\]

    D)            \[-{{e}^{-x}}+c\]

    Correct Answer: B

    Solution :

               \[\int_{{}}^{{}}{\left( 1+x+\frac{{{x}^{2}}}{2\,!}+\frac{{{x}^{3}}}{3\,!}+....... \right)\text{ }dx=\int_{{}}^{{}}{{{e}^{x}}dx={{e}^{x}}+c.}}\]


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