JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Fundamental Integration

  • question_answer
    \[\int_{{}}^{{}}{\sqrt{1+\sin \frac{x}{2}}\ dx=}\] [IIT 1980; MP PET 1989; Pb. CET 2003]

    A)            \[\frac{1}{4}\left( \cos \frac{x}{4}-\sin \frac{x}{4} \right)+c\]

    B)            \[4\left( \cos \frac{x}{4}-\sin \frac{x}{4} \right)+c\]

    C)            \[4\left( \sin \frac{x}{4}-\cos \frac{x}{4} \right)+c\]

    D)            \[4\left( \sin \frac{x}{4}+\cos \frac{x}{4} \right)+c\]

    Correct Answer: C

    Solution :

               \[\int_{{}}^{{}}{\sqrt{1+\sin \frac{x}{2}\,}}dx=\int_{{}}^{{}}{\sqrt{\left( {{\sin }^{2}}\frac{x}{4}+{{\cos }^{2}}\frac{x}{4}+2\sin \frac{x}{4}\cos \frac{x}{4} \right)}\,dx}\]                    \[=\int_{{}}^{{}}{\left( \sin \frac{x}{4}+\cos \frac{x}{4} \right)\,dx=4\left( \sin \frac{x}{4}-\cos \frac{x}{4} \right)}+c\].


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