A) \[{{x}^{3}}-\sqrt{x}+c\]
B) \[{{x}^{3}}+\sqrt{x}+c\]
C) \[{{x}^{3}}-2\sqrt{x}+c\]
D) \[{{x}^{3}}-4\sqrt{x}+c\]
Correct Answer: D
Solution :
\[\int_{{}}^{{}}{\frac{3{{x}^{3}}-2\sqrt{x}}{x}\,dx}=\int_{{}}^{{}}{3{{x}^{2}}dx}-2\int_{{}}^{{}}{{{x}^{-1/2}}dx}={{x}^{3}}-4\sqrt{x}+c\].
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