JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Fundamental Integration

  • question_answer
    \[\int_{{}}^{{}}{\frac{{{\sin }^{3}}x+{{\cos }^{3}}x}{{{\sin }^{2}}x{{\cos }^{2}}x}}\ dx=\]

    A)            \[\tan x+\cot x+c\]

    B)            \[\tan x-\cot x+c\]

    C)            \[\text{cosec}\,x-\cot x+c\]

    D)            \[\sec x-\text{cosec}\,x+c\]

    Correct Answer: D

    Solution :

               \[\int_{{}}^{{}}{\frac{{{\sin }^{3}}x+{{\cos }^{3}}x}{{{\sin }^{2}}x{{\cos }^{2}}x}\,dx}=\int_{{}}^{{}}{\left( \frac{\sin x}{{{\cos }^{2}}x}+\frac{\cos x}{{{\sin }^{2}}x} \right)\,dx}\]            \[=\frac{{{(x-5)}^{-2+1}}}{-2+1}+c=\frac{{{(x-5)}^{-1}}}{-1}+c\]\[=\sec x-\cos \text{ec}x+c\]


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