JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Fundamental Integration

  • question_answer
    \[\int_{{}}^{{}}{\frac{5({{x}^{6}}+1)}{{{x}^{2}}+1}dx=}\]

    A)            \[5({{x}^{7}}+x){{\tan }^{-1}}x+c\]

    B)            \[{{x}^{5}}-\frac{5}{3}{{x}^{3}}+5x+c\]

    C)            \[3{{x}^{4}}-5{{x}^{2}}+15x+c\]

    D)            \[5{{\tan }^{-1}}({{x}^{2}}+1)+\log ({{x}^{2}}+1)+c\]

    Correct Answer: B

    Solution :

               \[\int_{{}}^{{}}{\frac{5({{x}^{6}}+1)}{{{x}^{2}}+1}\,dx=\int_{{}}^{{}}{\frac{5({{x}^{2}}+1)({{x}^{4}}-{{x}^{2}}+1)}{({{x}^{2}}+1)}\,dx}}\]                    \[=\int_{{}}^{{}}{5({{x}^{4}}-{{x}^{2}}+1)\,dx={{x}^{5}}-\frac{5}{3}{{x}^{3}}+5x+c.}\]


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