A) \[x+2\log (x-1)+c\]
B) \[2x+2\log (x-1)+c\]
C) \[x+4\log (1-x)+c\]
D) \[x+4\log (x-1)+c\]
Correct Answer: D
Solution :
\[\int_{{}}^{{}}{\frac{{{x}^{2}}+x-6}{(x-2)(x-1)}\,dx}=\int_{{}}^{{}}{\frac{(x+3)(x-2)}{(x-2)(x-1)}\,dx}=\int_{{}}^{{}}{\frac{x+3}{x-1}\,dx}\] \[=\int_{{}}^{{}}{\frac{x-1}{x-1}\,dx+\int_{{}}^{{}}{\frac{4}{x-1}\,dx}}=x+4\log (x-1)+c\].You need to login to perform this action.
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