JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Fundamental Integration

  • question_answer
    \[\int_{{}}^{{}}{\frac{\sin x+\text{cosec}\,x}{\tan x}dx=}\]

    A)            \[\sin x-\text{cosec}\,x+c\]

    B)            \[\text{cosec}\,x-\sin x+c\]

    C)            \[\log \tan x+c\]

    D)            \[\log \cot x+c\]

    Correct Answer: A

    Solution :

               \[\int_{{}}^{{}}{\frac{\sin x+\text{cosec}\,x}{\tan x}}\,dx=\int_{{}}^{{}}{(\cos x+\text{cosec}\,x\cot x)\,dx}\]                                                                     \[=\sin x-\text{cosec}\,x+c\]


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