JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Fundamental Integration

  • question_answer
    \[\int_{{}}^{{}}{\frac{1}{\sqrt{1+\sin x}}dx}=\] [RPET 1996]

    A)            \[2\sqrt{2}\log \tan \left( \frac{\pi }{8}+\frac{x}{4} \right)+c\]

    B)            \[\frac{1}{\sqrt{2}}\log \tan \left( \frac{\pi }{8}+\frac{x}{4} \right)+c\]

    C)            \[\sqrt{2}\log \tan \left( \frac{\pi }{8}+\frac{x}{4} \right)+c\]

    D)            \[\frac{1}{2\sqrt{2}}\log \tan \left( \frac{\pi }{8}+\frac{x}{4} \right)+c\]

    Correct Answer: C

    Solution :

               \[\int_{{}}^{{}}{\frac{1}{\sqrt{1+\sin x}}}\,dx=\int_{{}}^{{}}{\frac{1}{\sqrt{2}\sin \left( \frac{\pi }{4}+\frac{x}{2} \right)}}\,dx\]            \[=\frac{1}{\sqrt{2}}\int_{{}}^{{}}{\text{cosec}\,\left( \frac{x}{\text{2}}+\frac{\pi }{4} \right)}\,dx=\sqrt{2}\log \tan \left( \frac{\pi }{8}+\frac{x}{4} \right)+c.\]


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