A) \[\log \tan \left( \frac{\pi }{8}+\frac{x}{2} \right)+c\]
B) \[-\log (\sec x-\tan x)+c\]
C) \[\log (\sec x-\tan x)+c\]
D) None of these
Correct Answer: B
Solution :
\[\int_{{}}^{{}}{\sec x\,dx}=\log (\sec x+\tan x)+c\] \[=\log \left( \frac{1}{\sec x-\tan x} \right)+c=-\log (\sec x-\tan x)+c\].
You need to login to perform this action.
You will be redirected in
3 sec
