A) \[\cot x+c\]
B) \[-\cot x+c\]
C) \[{{\tan }^{2}}x+c\]
D) \[-{{\cot }^{2}}x+c\]
Correct Answer: B
Solution :
\[\int_{{}}^{{}}{\text{cose}{{\text{c}}^{\text{2}}}x\,dx}=-\cot x+c\].
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