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JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Fundamental Integration

  • question_answer
    \[\int_{{}}^{{}}{\left( 2\sin x+\frac{1}{x} \right)\ dx}\] is equal to [MP PET 1999]

    A)            \[-2\cos x+\log x+c\]

    B)            \[2\cos x+\log x+c\]

    C)            \[-2\sin x-\frac{1}{{{x}^{2}}}+c\]

    D)            \[-2\cos x+\frac{1}{{{x}^{2}}}+c\]

    Correct Answer: A

    Solution :

               \[\int_{{}}^{{}}{\left( 2\sin x+\frac{1}{x} \right)\,dx=-2\cos x+\log x+c}\].


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