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JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Fundamental Integration

  • question_answer
    \[\int_{{}}^{{}}{{{\tan }^{2}}x\ dx}\] is equal to [SCRA 1996]

    A)            \[\tan x+x+c\]

    B)            \[\tan x-x+c\]

    C)            \[\sec x+x+c\]

    D)            \[\sec x-x+c\]

    Correct Answer: B

    Solution :

               \[\int_{{}}^{{}}{{{\tan }^{2}}x\,dx}=\int_{{}}^{{}}{({{\sec }^{2}}x-1)\,dx}=\tan x-x+c\].


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