A) \[\frac{1}{-3{{x}^{3}}}+c\]
B) \[\frac{1}{3{{x}^{3}}}+c\]
C) \[\frac{1}{-4{{x}^{3}}}+c\]
D) \[-\frac{1}{3{{x}^{2}}}+c\]
Correct Answer: A
Solution :
\[\int_{{}}^{{}}{{{x}^{-4}}dx}=\frac{{{x}^{-3}}}{-3}+c=-\frac{1}{3{{x}^{3}}}+c.\]You need to login to perform this action.
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