A) \[\sin x+c\]
B) \[-\cos x+c\]
C) \[{{e}^{\log (\cos x)}}+c\]
D) None of these
Correct Answer: B
Solution :
\[\int_{{}}^{{}}{{{e}^{\log (\sin x)}}dx}=\int_{{}}^{{}}{\sin x\,dx}=-\cos x+c.\]
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