A) 2
B) 0
C) 4
D) 6
Correct Answer: B
Solution :
\[{{({{\sin }^{2}}\theta +{{\cos }^{2}}\theta )}^{3}}={{(1)}^{3}}\] \[\Rightarrow \,\,{{\sin }^{6}}\theta +{{\cos }^{6}}\theta +3\,{{\sin }^{2}}\theta \,{{\cos }^{2}}\theta =1\] and \[{{\sin }^{4}}\theta +{{\cos }^{4}}\theta +2\,{{\sin }^{2}}\theta \,{{\cos }^{2}}\theta =1\] Both gives, \[2\,\,({{\sin }^{6}}\theta +{{\cos }^{6}}\theta )-3\,({{\sin }^{4}}\theta +{{\cos }^{4}}\theta )+1=0\].You need to login to perform this action.
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