A) 1
B) 0
C) - 1
D) None of these
Correct Answer: B
Solution :
Since \[\sin 190{}^\circ =-\sin 10{}^\circ ,\ \sin 200{}^\circ =-\sin 20{}^\circ ,\] \[\sin 210{}^\circ =-\sin 30{}^\circ ,\ \sin 360{}^\circ =\sin 180{}^\circ =0\]etc.You need to login to perform this action.
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