A) 0
B) 1
C) 2
D) 1/2
Correct Answer: A
Solution :
\[\sin \theta +\cos \theta =1\] Squaring on both sides, we get \[\Rightarrow {{\sin }^{2}}\theta +{{\cos }^{2}}\theta +2\sin \theta \cos \theta =1\] \[\therefore \sin \theta \cos \theta =0\].You need to login to perform this action.
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