A) \[\sin B\]
B) \[\sin 2B\]
C) \[\sin 3B\]
D) None of these
Correct Answer: B
Solution :
\[A+B=45{}^\circ ,\]therefore \[2A=90{}^\circ -2B\] \[\therefore \cos 2A=\sin 2B\].You need to login to perform this action.
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