A) 0
B) -1
C) 1/2
D) 1
Correct Answer: D
Solution :
\[\cos (270+\theta )\cos (90-\theta )-\sin (270-\theta )\cos \theta \] \[=\sin \theta .\sin \theta +\cos \theta .\cos \theta =1\].You need to login to perform this action.
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