A) Half of the atomic weight
B) 1/5 of the atomic weight
C) The atomic weight
D) Twice the atomic weight
Correct Answer: C
Solution :
The atomic weight; \[\text{Equivalent weight }=\text{ }\frac{\text{Atomic weight}}{\text{ No}\text{. of }{{\text{e}}^{}}\text{lost or gained}}\] \[F{{e}^{2+}}\,\to \,F{{e}^{3+}}+{{e}^{-}}\] \ Equivalent weight = Atomic weightYou need to login to perform this action.
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