A) 3-chloropropanoic acid
B) 2-chloropropanoic acid
C) 2-chloroethanoic acid
D) Chlorosuccinic acid
Correct Answer: A
Solution :
\[\underset{\text{3 chloro propanoic acid}}{\mathop{Cl-\underset{3}{\mathop{C}}\,{{H}_{2}}-\underset{2}{\mathop{C}}\,{{H}_{2}}-\underset{1}{\mathop{C}}\,OOH}}\,\]You need to login to perform this action.
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