A) An unsaturated hydroxy compound
B) A keto compound
C) Both of these ways
D) None of these
Correct Answer: C
Solution :
\[\underset{\begin{smallmatrix} \text{Acetoacetic ester} \\ \text{ ( keto form)} \end{smallmatrix}}{\mathop{C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O-{{C}_{2}}{{H}_{5}}}}\,\] ⇌ \[\underset{\text{(enolic form)}}{\mathop{C{{H}_{3}}-\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,=}}\,CH-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O-{{C}_{2}}{{H}_{5}}}}\,\]You need to login to perform this action.
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