A) \[ClC{{H}_{2}}COOH\]
B) \[{{C}_{6}}{{H}_{5}}COOH\]
C) \[C{{D}_{3}}COOH\]
D) \[C{{H}_{3}}C{{H}_{2}}COOH\]
Correct Answer: A
Solution :
Any electron withdrawing substituent (having-I-effect) stabilises the anion by dispersing the negative charge and therefore, increases the acidity. Chlorine is an electron withdrawing group.You need to login to perform this action.
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