A) Ethylene
B) Ethylene chlorohydrin
C) Ethyl acetate
D) Ethylmethyl ketone
Correct Answer: A
Solution :
\[\underset{\text{Ethylene}\,}{\mathop{n\,C{{H}_{2}}=C{{H}_{2}}}}\,\,\to \underset{\,\,\text{Polythene}}{\mathop{{{(-C{{H}_{2}}-C{{H}_{2}}-)}_{n}}}}\,\]
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