A) \[C{{F}_{2}}=C{{F}_{2}}\]
B) \[C{{H}_{2}}=CHCl\]
C) \[CC{{l}_{2}}=CC{{l}_{2}}\]
D) \[C{{H}_{2}}=\overset{\,\,Cl}{\mathop{\overset{|}{\mathop{C}}\,}}\,-CH=C{{H}_{2}}\]
Correct Answer: D
Solution :
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